[leetCode] 468. Validate IP Address (Python)

Given a string IP, return "IPv4" if IP is a valid IPv4 address, "IPv6" if IP is a valid IPv6 address or "Neither" if IP is not a correct IP of any type.

A valid IPv4 address is an IP in the form "x1.x2.x3.x4" where 0 <= xi <= 255 and xi cannot contain leading zeros. For example, "192.168.1.1" and "192.168.1.0" are valid IPv4 addresses but "192.168.01.1", while "192.168.1.00" and "192.168@1.1" are invalid IPv4 addresses.

A valid IPv6 address is an IP in the form "x1:x2:x3:x4:x5:x6:x7:x8" where:

• 1 <= xi.length <= 4
• xi is a hexadecimal string which may contain digits, lower-case English letter ('a' to 'f') and upper-case English letters ('A' to 'F').
• Leading zeros are allowed in xi.

For example, "2001:0db8:85a3:0000:0000:8a2e:0370:7334" and "2001:db8:85a3:0:0:8A2E:0370:7334" are valid IPv6 addresses, while "2001:0db8:85a3::8A2E:037j:7334" and "02001:0db8:85a3:0000:0000:8a2e:0370:7334" are invalid IPv6 addresses.

 

Example 1:

Input: IP = "172.16.254.1"
Output: "IPv4"
Explanation: This is a valid IPv4 address, return "IPv4".

Example 2:

Input: IP = "2001:0db8:85a3:0:0:8A2E:0370:7334"
Output: "IPv6"
Explanation: This is a valid IPv6 address, return "IPv6".

Example 3:

Input: IP = "256.256.256.256"
Output: "Neither"
Explanation: This is neither a IPv4 address nor a IPv6 address.

Example 4:

Input: IP = "2001:0db8:85a3:0:0:8A2E:0370:7334:"
Output: "Neither"

Example 5:

Input: IP = "1e1.4.5.6"
Output: "Neither"

 

Constraints:

• IP consists only of English letters, digits and the characters '.' and ':'.

Solution

class Solution:
    def validIPAddress(self, IP: str) -> str:
        def checkIPv4(IP):
            ip_split = IP.split(".")

            for ip in ip_split:
                if len(ip) == 0 or len(ip) > 3 or  ip.isdigit() == False or (ip[0] == '0' and len(ip) != 1) or int(ip) > 255:
                    return "Neither" 
            return 'IPv4'
        
        def checkIPv6(IP):
            ip_split = IP.split(":")

            for ip in ip_split:
                if len(ip) == 0 or len(ip) > 4:
                    return "Neither"
                for c in ip:
                     if c.lower() not in '0123456789abcdef':
                        return "Neither" 
            return "IPv6"

        
        if len(IP.split("."))-1 == 3:
            return checkIPv4(IP)
        elif len(IP.split(":"))-1 == 7:
            return checkIPv6(IP)
        
        return "Neither"

SOMJANG/CODINGTEST_PRACTICE