Notice
Recent Posts
Recent Comments
일 | 월 | 화 | 수 | 목 | 금 | 토 |
---|---|---|---|---|---|---|
1 | 2 | 3 | 4 | 5 | 6 | 7 |
8 | 9 | 10 | 11 | 12 | 13 | 14 |
15 | 16 | 17 | 18 | 19 | 20 | 21 |
22 | 23 | 24 | 25 | 26 | 27 | 28 |
29 | 30 | 31 |
Tags
- 맥북
- AI 경진대회
- 백준
- 코로나19
- Real or Not? NLP with Disaster Tweets
- Docker
- gs25
- 파이썬
- 자연어처리
- 프로그래머스
- ubuntu
- 편스토랑 우승상품
- leetcode
- programmers
- 우분투
- 편스토랑
- 캐치카페
- ChatGPT
- 금융문자분석경진대회
- Git
- Baekjoon
- SW Expert Academy
- 더현대서울 맛집
- github
- 데이콘
- PYTHON
- dacon
- hackerrank
- 프로그래머스 파이썬
- Kaggle
Archives
- Today
- Total
솜씨좋은장씨
[leetCode] 819. Most Common Word (Python) 본문
728x90
반응형
Given a paragraph and a list of banned words, return the most frequent word that is not in the list of banned words. It is guaranteed there is at least one word that isn't banned, and that the answer is unique.
Words in the list of banned words are given in lowercase, and free of punctuation. Words in the paragraph are not case sensitive. The answer is in lowercase.
Example:
Input:
paragraph = "Bob hit a ball, the hit BALL flew far after it was hit."
banned = ["hit"]
Output: "ball"
Explanation:
"hit" occurs 3 times, but it is a banned word.
"ball" occurs twice (and no other word does), so it is the most frequent non-banned word in the paragraph.
Note that words in the paragraph are not case sensitive,
that punctuation is ignored (even if adjacent to words, such as "ball,"),
and that "hit" isn't the answer even though it occurs more because it is banned.
Note:
- 1 <= paragraph.length <= 1000.
- 0 <= banned.length <= 100.
- 1 <= banned[i].length <= 10.
- The answer is unique, and written in lowercase (even if its occurrences in paragraph may have uppercase symbols, and even if it is a proper noun.)
- paragraph only consists of letters, spaces, or the punctuation symbols !?',;.
- There are no hyphens or hyphenated words.
- Words only consist of letters, never apostrophes or other punctuation symbols.
Solution
from collections import Counter
import re
class Solution:
def mostCommonWord(self, paragraph: str, banned: List[str]) -> str:
paragraph = paragraph.lower()
paragraph = re.sub('[^a-z]',' ',paragraph)
paragraph_list = paragraph.split(' ')
paragraph_list = [para for para in paragraph_list if para not in banned and para != '']
cnt_dict = Counter(paragraph_list)
val_list = list(cnt_dict.items())
print(val_list)
sorted_list = sorted(val_list, key=lambda x: -x[1])
print(sorted_list)
answer = sorted_list[0][0]
return answer
'Programming > 코딩 1일 1문제' 카테고리의 다른 글
[leetCode] 383. Ransom Note (Python) (0) | 2020.07.19 |
---|---|
[leetCode] 9. Palindrome Number (Python) (0) | 2020.07.18 |
[leetCode] 372. Super Pow (Python) (0) | 2020.07.15 |
[leetCode] 371. Sum of Two Integers (Python) (0) | 2020.07.14 |
[leetCode] 1. Two Sum (Python) (0) | 2020.07.13 |
Comments