Notice
Recent Posts
Recent Comments
일 | 월 | 화 | 수 | 목 | 금 | 토 |
---|---|---|---|---|---|---|
1 | 2 | 3 | 4 | 5 | 6 | 7 |
8 | 9 | 10 | 11 | 12 | 13 | 14 |
15 | 16 | 17 | 18 | 19 | 20 | 21 |
22 | 23 | 24 | 25 | 26 | 27 | 28 |
29 | 30 | 31 |
Tags
- 백준
- gs25
- PYTHON
- ChatGPT
- 파이썬
- 데이콘
- Docker
- Git
- hackerrank
- programmers
- 금융문자분석경진대회
- SW Expert Academy
- AI 경진대회
- 편스토랑 우승상품
- github
- dacon
- 자연어처리
- 프로그래머스
- 우분투
- 더현대서울 맛집
- Baekjoon
- 캐치카페
- Kaggle
- leetcode
- 맥북
- ubuntu
- 코로나19
- Real or Not? NLP with Disaster Tweets
- 프로그래머스 파이썬
- 편스토랑
Archives
- Today
- Total
솜씨좋은장씨
[leetCode] 35. Search Insert Position (Python) 본문
728x90
반응형
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Example 1:
Input: [1,3,5,6], 5
Output: 2
Example 2:
Input: [1,3,5,6], 2
Output: 1
Example 3:
Input: [1,3,5,6], 7
Output: 4
Example 4:
Input: [1,3,5,6], 0
Output: 0
Solution
class Solution:
def searchInsert(self, nums: List[int], target: int) -> int:
if target in nums:
return nums.index(target)
else:
cnt = 0
for i in nums:
if i > target :
return cnt
cnt = cnt + 1
return len(nums)
'Programming > 코딩 1일 1문제' 카테고리의 다른 글
[leetCode] 345. Reverse Vowels of a String (Python) (0) | 2020.08.07 |
---|---|
[leetCode] 448. Find All Numbers Disappeared in an Array (Python) (0) | 2020.08.06 |
[leetCode] 290. Word Pattern (Python) (0) | 2020.08.04 |
[leetCode] 205. Isomorphic Strings (Python) (0) | 2020.08.03 |
[leetCode] 434. Number of Segments in a String (Python) (0) | 2020.08.02 |
Comments