[Programmers] 2022 KAKAO TECH INTERNSHIP - 성격 유형 검사하기 (Python)

코딩 1일 1문제! 오늘의 문제는 프로그래머스의 2022 KAKAO TECH INTERNSHIP 성격 유형 검사 하기 입니다.

프로그래머스

👨🏻‍💻 코드 ( Solution )

def get_character_score(question, choice, score_list):
    if 1 <= choice <= 4:
        character_type = question[0]
        score = score_list[choice-1]
    elif 5 <= choice <= 7:
        character_type = question[1]
        score = score_list[choice-1]
        
    return character_type, score


def get_high_score_character(score_dict, character1, character2):
    if score_dict[character1] > score_dict[character2]:
        high_score_character = character1
    elif score_dict[character1] < score_dict[character2]:
        high_score_character = character2
    else:
        high_score_character = min(character1, character2)
        
    return high_score_character


def make_character_type_string(score_dict):
    character_type_string = ""
    character_list = [
        ("R", "T"), ("C", "F"), ("J", "M"), ("A", "N")
    ]
    
    for character in character_list:
        high_score_character = get_high_score_character(
            score_dict=score_dict, 
            character1=character[0], character2=character[1]
        )
        character_type_string += high_score_character
        
    return character_type_string


def solution(survey, choices):
    character_type_score_dict = {
        "R": 0, "T": 0, "C": 0, "F": 0,
        "J": 0, "M": 0, "A": 0, "N": 0
    }
    score_list = [3, 2, 1, 0, 1, 2, 3]
    
    for question, choice in zip(survey, choices):
        character_type, score = get_character_score(
            question=question, choice=choice, score_list=score_list
        )
        
        character_type_score_dict[character_type] += score
        
    return make_character_type_string(score_dict=character_type_score_dict)

GitHub - SOMJANG/CODINGTEST_PRACTICE: 1일 1문제 since 2020.02.07