[BaekJoon] 5235번 : Even Sum More Than Odd Sum (Python)

코딩 1일 1문제! 오늘의 문제는 백준의 Even Sum More than Odd Sum 입니다.

5235번: Even Sum More Than Odd Sum

👨🏻‍💻 코드 ( Solution )

def divide_numbers_odd_even(number_list):
    odd_numbers = [num for num in number_list if num % 2 == 1]
    even_numbers = [num for num in number_list if num % 2 == 0]
    
    return odd_numbers, even_numbers


def sum_numbers(number_list):
    return sum(number_list) if number_list else 0


def compare_odd_even_sum(odd_sum, even_sum):
    result = "TIE"
    if odd_sum > even_sum:
        result = "ODD"
    elif odd_sum < even_sum:
        result = "EVEN"
        
    return result


def even_sum_more_than_odd_sum(number_list):
    odd_numbers, even_numbers = divide_numbers_odd_even(
        number_list=number_list[1:]
    )
    
    odd_sum = sum_numbers(number_list=odd_numbers)
    even_sum = sum_numbers(number_list=even_numbers)

    compare_result = compare_odd_even_sum(
        odd_sum=odd_sum, even_sum=even_sum
    )
    
    return compare_result
    
    
if __name__ == "__main__":
    for _ in range(int(input())):
        number_list = list(map(int, input().split()))
        
        print(even_sum_more_than_odd_sum(number_list=number_list))

GitHub - SOMJANG/CODINGTEST_PRACTICE: 1일 1문제 since 2020.02.07