[BaekJoon] 1267번 : 핸드폰 요금 (Python)

코딩 1일 1문제! 오늘의 문제는 백준의 핸드폰 요금 입니다.

1267번: 핸드폰 요금

👨🏻‍💻 코드 ( Solution )

def minsik_plan(call_time):
    fee = 0
    
    if call_time < 60:
        fee = 15
    elif 60 <= call_time < 120:
        fee = 30
    else:
        fee = (call_time // 60) * 15 + 15
        
    return fee
    
    
def youngsik_plan(call_time):
    fee = 0
    
    if call_time < 30:
        fee = 10
    elif 30 <= call_time < 60:
        fee = 20
    else:
        fee = (call_time // 30) * 10 + 10
        
    return fee


def compare_plan(youngsik_plan_fee, minsik_plan_fee):
    result = ""
    if youngsik_plan_fee == minsik_plan_fee:
        result = f"Y M {youngsik_plan_fee}"
    elif youngsik_plan_fee < minsik_plan_fee:
        result = f"Y {youngsik_plan_fee}"
    else:
        result = f"M {minsik_plan_fee}"
        
    return result
        
    

def choice_plan(N, call_time_list):
    youngsik_plan_fee, minsik_plan_fee = 0, 0
    
    for call_time in call_time_list:
        youngsik_plan_fee += youngsik_plan(call_time)
        minsik_plan_fee += minsik_plan(call_time)
        
    return compare_plan(youngsik_plan_fee, minsik_plan_fee)
    
    
if __name__ == "__main__":
    N = int(input())
    call_time_list = list(map(int, input().split()))
    
    print(choice_plan(N, call_time_list))

GitHub - SOMJANG/CODINGTEST_PRACTICE: 1일 1문제 since 2020.02.07