[leetCode] 1550. Three Consecutive Odds (Python)

Given an integer array arr, return true if there are three consecutive odd numbers in the array. Otherwise, return false.

 

Example 1:

Input: arr = [2,6,4,1]
Output: false
Explanation: There are no three consecutive odds.

Example 2:

Input: arr = [1,2,34,3,4,5,7,23,12]
Output: true
Explanation: [5,7,23] are three consecutive odds.

Constraints:

• 1 <= arr.length <= 1000
• 1 <= arr[i] <= 1000

Solution

class Solution:
    def threeConsecutiveOdds(self, arr: List[int]) -> bool:
        cnt = 0
        
        for num in arr:
            if num % 2 == 1:
                cnt = cnt + 1
                
                if cnt == 3:
                    return True
            else:
                cnt = 0
                
        return False

 

Solution

class Solution:
    def threeConsecutiveOdds(self, arr: List[int]) -> bool:
        if len(arr) < 3:
            return False
                
        for i in range(len(arr)-2):
            if (arr[i] % 2 == 1) and (arr[i+1] % 2 == 1) and (arr[i+2] % 2 == 1):
                return True
            
        return False

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